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15x^2+170x+400=0
a = 15; b = 170; c = +400;
Δ = b2-4ac
Δ = 1702-4·15·400
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(170)-70}{2*15}=\frac{-240}{30} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(170)+70}{2*15}=\frac{-100}{30} =-3+1/3 $
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